1: 2: 3: 4: 5: 6:
for (i=0; i<= noOfClients-1; i++) { für (k=1; k<=noOfObjects-1; k++) { Lambda [i] [k] =1+, % (des Rands () 1); printf („Lambda [%d] [%d] = %.lf \ n“, i, k, Lambda [i] [k]); } }