(1): 2: 3: 4: 5: 6:
for (i=0; i<= noOfClients-1; i++) { dla (k=1; k<=noOfObjects-1; k++) { lambda [i] [k] =1+ (skraj () % 1); printf ("lambda [%d] [%d] = %.lf \ n", i, k, lambda [i] [k]); } }