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Question : in T-sql how to find 80% a one value based on other
i have joined view and a table. I have following 4 columns
ProjectName Quoted Actual Balance
in my t-sql script i have a case as below. I want to find:
When Actuals are less then Quoted
and Actual which have exceed 80% of Quoted.
I am entering the following case however i am getting convert to varchar or numeric error prompt, please can you fix the below statement
CASE
WHEN actual < quoted and WHEN actual >(quoted * .80)
Answer : in T-sql how to find 80% a one value based on other
what are the data types of the 2 columns?
also, you "requested logic" seems incorrect?
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