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Question : Fields not being read from CSV
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When uploading a CSV with just 93 rows, the first 16 rows go smoothly until the 17th row.
This is the 16th row (which works, perfectly):
string(625) "'1592', '203', 'UNUSED', '', '', '0', 'NTTQ4040E6-N', 'NTTQ4040E6 - WLAN Handset 61xx Belt Clip Ratchet Accessory (UNUSED) - NORTEL WLAN', 'ReLogisTechs offers a full line of Nortel WLAN products, such as the NTTQ4040E6 - WLAN Handset 61xx Belt Clip Ratchet Accessory (UNUSED) - NORTEL WLAN. If you are looking for any additional Nortel WLAN products that are not list on www.relogistechs.com or you have additional questions about the NTTQ4040E6 - WLAN Handset 61xx Belt Clip Ratchet Accessory (UNUSED) - NORTEL WLAN, please call or contact us today.', '', '', 'NTTQ4040E6-N', '', '', '5', '10', '8', '6', '', '', '', ''"
This is the 17th row (which fails):
string(629) "'1593', '203', 'Refurbished', '', '', '0', 'NTTQ4040E6-R', 'NTTQ4040E6 - WLAN Handset 61xx Belt Clip Ratchet Accessory (Refurbished) - NORTEL WLAN', 'ReLogisTechs offers a full line of Nortel WLAN products, such as the NTTQ4040E6 - WLAN Handset 61xx Belt Clip Ratchet Accessory (Refurbished) - NORTEL WLAN. If you are looking for any additional Nortel WLAN products that are not list on www.relogistechs.com or you have additional questions about the NTTQ4040E6 - WLAN Handset 61xx Belt Clip Ratchet Accessory (Refurbished) - NORTEL WLAN, please call or contact us today.', '', '', 'NTTQ4040E6-R', '', '', '5', '10', '8', '6'"
Notice, the 16th row has four blank values at the end. The 17th row does not. Why does the 17th row omit these values thus creating the error below:
Mysql errno: 1136
Mysql error: Column count doesn't match value count at row 1
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// ESCAPE THE INFORMATION FOR USE IN THE QUERY
foreach ($csvdata as $ptr => $value)
{
$csvdata[$ptr] = mysql_real_escape_string($value);
}
// SET UP VALUE FIELDS
$query_data = "'" . implode("', '", $csvdata) . "'";
print "<pre>";
var_dump($query_data);
print "</pre>";
$query_data = str_replace("''", "NULL", $query_data);
// SET UP A QUERY
$sql = "REPLACE INTO items ( $query_cols ) VALUES ( $query_data )";
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Answer : Fields not being read from CSV
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Sorry, I send my post incomplete...
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$query_data = str_replace("''", "NULL", $query_data);
$query_data.= str_repeat(', NULL', count(explode(',',$query_cols))-count($csvdata))
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