Question : Load list.txt to bat file

Hi Experts!

We have in a Directory the files:


request0001_1.file
request0001_2.file
request0001_3.file
request0002_1.file
request0002_2.file
request0003_1.file
request0004_1.file
request0004_2.file


We make a file named list.txt with the content separeted by ";":


request0001;request0001_1.file;worksheet2010.xls
request0001;request0001_2.file;plan.pdf
request0001;request0001_3.file;plan2010.doc
request0002;request0002_1.file;controll2010.doc
request0002;request0002_2.file;image.jpg
request0003;request0003_1.file;work_2010.xls
request0004;request0004_1.file;plan.pdf
request0004;request0004_2.file;photo.gif


Where:
- The first column is the name of the folder should be created;
- The second column is the current file name;
- The third column is the name that the file should be (to be renamed)


I need load this list to loop do the following action(As the example below):

mkdir request0001
rename request0001_1.file worksheet2010.xls
move worksheet2010.xls request0001


The result is the structure:

request0001
      file;worksheet2010.xls
      plan.pdf
      plan2010.doc
request0002
      file;controll2010.doc
      image.jpg
request0003
      work_2010.xls
request0004
      plan.pdf
      photo.gif


How can i do this loop?

Answer : Load list.txt to bat file

This should do it.

for /f "tokens=1,2,3 delims=;" %%a in ('type list.txt') do (
    md "%%a"
    ren "%%b" "%%c"
    move "%%c" "%%a"
)