  # Question : Why does a LED burn out.

## Answer : Why does a LED burn out.

##### "Forward Voltage Drop""Electricity uses up a little energy pushing its way through the diode, rather like a person pushing through a door with a spring. This means that there is a small voltage across a conducting diode, it is called the forward voltage drop and is about 0.7V for all normal diodes which are made from silicon. The forward voltage drop of a diode is almost constant whatever the current passing through the diode so they have a very steep characteristic (current-voltage graph)."     http://www.kpsec.freeuk.com/components/diode.htmBeyond this 0.7V forward voltage, the dynamic resistance is almost 0. So, a 1V source may cause a current large enough to burn out the LED. So, you need a limiting resistor.======"An LED must have a resistor connected in series to limit the currentthrough the LED, otherwise it will burn out almost instantly.""The resistor value, R is given by:"   R = ( VS - VL ) / I"VS = supply voltage"VL = LED voltage (usually 2V, but 4V for blue and white LEDs)"I = LED current (e.g. 10mA = 0.01A, or 20mA = 0.02A)"Make sure the LED current you choose is less than the maximum permitted and convert the current to amps (A) so the calculation will give the resistor value in ohms (ohm)."    http://www.kpsec.freeuk.com/components/led.htm
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