# Question : Need a solution for Sum within a Sum

## Answer : Need a solution for Sum within a Sum

##### Can you try this: ```1: 2: 3: 4: 5: 6: 7: 8: 9: 10: 11: 12: 13: 14: 15: 16: ``` ```SELECT [Year], [Month], Loc, [Total Bookings], [Revenue in USD], [Revenue in USD] / Leg_sum as 'Rev / Res' FROM ( SELECT b.Year, DateName(mm,DATEADD(mm,b.Month, -1)) as 'Month', a.Loc, SUM(ISNULL(CASE WHEN A.[Type] = 'NEW' AND A.Leg = 1 THEN 1 ELSE 0 END, 0)) - SUM(ISNULL(CASE WHEN a.[Type] = 'CAN' AND a.Leg = 1 THEN 1 ELSE 0 END, 0)) AS 'Total Bookings', SUM(ISNULL(CASE WHEN A.[Type] = 'NEW' THEN (a.Revenue * e.To_USD_Rate) END, 0)) - SUM(ISNULL(CASE WHEN a.[Type] = 'CAN' THEN (a.Revenue * e.To_USD_Rate) END, 0)) AS 'Revenue in USD', SUM(a.Leg) AS Leg_sum FROM Bookings a LEFT OUTER JOIN Calendar b on b.Date_ID = a.Arrival_Date LEFT OUTER JOIN Exchange_Rates e on e.Currency = a.Currency WHERE a.Loc = 'RYH' AND b.Month IN (MONTH(b.Year), MONTH(b.Year)+1, MONTH(b.Year)+2) AND b.Year IN (Year(GETDATE()), Year(GETDATE())-1) GROUP BY b.year, DateName(mm,DATEADD(mm,b.Month, -1)), a.Loc ) temp Order BY [Year], [Month] ```
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