Question : TSQL last 30 dates in Ascending order?

How do I get, witihin TSQL & in a single TSQL statement, the last 30 dates in ascending order?
I am able to get the last 30 dates as follows but they are in Descending order.
SELECT distinct TOP (30) createdate FROM History ORDER BY createdate desc

Example: using the4 code above 30 dates: comes up as
06/30, 06/29, 06/28....... 06/02, 06/01
I need them to apear as
06/10, 06/02.... 06/29, 06/30

Background, I am using therse dates within Google charts, which has a ~2000 URL limit, so I use a subset of the dates, and I want a recent subset of the data, so I use the last 30 dayes collected.
The dates on the chart should appear from left to right , in ascending order.

Answer : TSQL last 30 dates in Ascending order?

try the below

                       
             SELECT Emp_Name, Hire_Date, datepart([Year],Hire_Date) as YYYY, datepart([Month],Hire_Date) as MM
FROM Table1
where Hire_Date >= dateadd(m, datediff(m, 0, getdate())-13, 0)

Question : TSQL last 30 dates in Ascending order?

Answer : TSQL last 30 dates in Ascending order?

try the below 1: 2: 3: SELECT Emp_Name, Hire_Date, datepart([Year],Hire_Date) as YYYY, datepart([Month],Hire_Date) as MM FROM Table1 where Hire_Date >= dateadd(m, datediff(m, 0, getdate())-13, 0)

try the below

1: 2: 3:

SELECT Emp_Name, Hire_Date, datepart([Year],Hire_Date) as YYYY, datepart([Month],Hire_Date) as MM FROM Table1 where Hire_Date >= dateadd(m, datediff(m, 0, getdate())-13, 0)