Question : Why do I get an incorrect number?

Given the code and database attached, I had expected to get a print out of "max_number: 10". Instead I get "max_number: 9". Can anyone of you gurus of MySQL explain that for me?

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<?php
error_reporting(E_ALL|E_STRICT); 
ini_set('display_errors', '1');
include "whatever/dbconfig.php";  
@mysql_connect($host,$usr,$pwd) or die("<p>No connection.</p>");  
@mysql_select_db($db) or die("<p>Cannot connect" . $db . ".</p>");   
$SQL = " SELECT MAX(number) as max_number FROM table WHERE date = '2010-09-04' AND place = 'Kranen'  AND number <= 29 ";
$ret = mysql_query($SQL);
if (!$ret) { echo(mysql_error()); }
else {
	while ($row = mysql_fetch_array($ret)) {
        $max_number  = $row["max_number"];
        
		 
		echo "max_number: $max_number";
	}}
?>

Attachments:

db.gif (7 KB) (File Type Details)

Print out of relevant part of database

Answer : Why do I get an incorrect number?

your field "numberi" is very likely of data type varchar, in which MAX() will indeed return "9" and not "10"

change the field to numerical data type, and the order by as well as MAX will work on numerical comparison and not string comparison

you could also try:

MAX(yourfield + 0)

Question : Why do I get an incorrect number?

Answer : Why do I get an incorrect number?

your field "numberi" is very likely of data type varchar, in which MAX() will indeed return "9" and not "10"change the field to numerical data type, and the order by as well as MAX will work on numerical comparison and not string comparisonyou could also try:MAX(yourfield + 0)

your field "numberi" is very likely of data type varchar, in which MAX() will indeed return "9" and not "10"

change the field to numerical data type, and the order by as well as MAX will work on numerical comparison and not string comparison

you could also try:

MAX(yourfield + 0)