Microsoft
Software
Hardware
Network
Question : basic calculus - finding the maxium
Hi
If you have R = D^2(C/2 - D/3)
Then isn't dR/dD = CD -D^2 so that you have max/min points when D=0 or D=C?
I must be making silly mistake as the book says the max point is when D = C/2
thanks
Answer : basic calculus - finding the maxium
R(x) = x^2(C/2 - x/3) = (C/2) * x^2 - x^3 /3
R'(x) = (C/2) *2 x - 3 x^2 /3
R'(x) = C x - x^2 = C x - x^2 = x ( C - x )
R'(x) = 0, when x = C and x = 0
Random Solutions
Can't Import javax.tv.Xlet within Java ME project class
PDF Mail Merge with iTextSharp
Can't login to Lacie d2
Internal server name showing in URL
Display of base64 images in IE
Isolating a word on a row in Access
urgent need of EMC DMX/Symmetrix documention on Solaris10, need to attend personal interview as Solaris 10 system administrator.
Cannot tracert beyond DSL modem
Backup to Remote PC - Backup Exec 10d
Windows SBS 2003