Question : phase difference of trig functions

Hi

I don't understand why the phase difference between sin(3x + pi/8) relative to sin(3x) is pi/24

Taking a simple example of the phase difference between sin(x+pi/4) relative to sin(x) it seems fairly straight forward to see there that the phase difference is pi/4 because, in my thinking, you have to add pi/4 on to x for sin(x) to catch up with sin(x+pi/4).

I would have thought the phase difference between sin(3x + pi/8) relative to sin(3x) was simply pi/8 so I must be missing something obvious

thanks

Answer : phase difference of trig functions

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