Question : Order of constructor calls

Duplicating Objects using a Constructor
Hi,

I was running following example

Order of constructor calls

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class Meal {
  Meal() {
    System.out.println("Meal()");
  }
}

class Bread {
  Bread() {
    System.out.println("Bread()");
  }
}

class Cheese {
  Cheese() {
    System.out.println("Cheese()");
  }
}

class Lettuce {
  Lettuce() {
    System.out.println("Lettuce()");
  }
}

class Lunch extends Meal {
  Lunch() {
    System.out.println("Lunch()");
  }
}

class PortableLunch extends Lunch {
  PortableLunch() {
    System.out.println("PortableLunch()");
  }
}

class Sandwich extends PortableLunch {
  private Bread b = new Bread();

  private Cheese c = new Cheese();

  private Lettuce l = new Lettuce();

  public Sandwich() {
    System.out.println("Sandwich()");
  }
}

public class class10 {
  public static void main(String[] args) {
    new Sandwich();
  }
} 
 

getting output like

Meal()
Lunch()
PortableLunch()
Bread()
Cheese()
Lettuce()
Sandwich()

I was not sure why output has Bread Cheese, Lettuse.

I was not clear on the output, flow of execution, concept behind the program. Any ideas, links, suggestions, resources, sample code highly appreciated. Thanks in advance

Question : Order of constructor calls

Answer : Order of constructor calls

whenever a constructor is called, the parent classes constructor needs to be called (first)