Question : How to convert a stream with output escaping enabled to proper format XML that can be loaded in a XMLDocument object?

If I receive an input stream like below, how can I convert it to a proper XML?
I tried using String replace to replace the &lt; with < and &gt; with > but then if the node value also contains &lt; then that is also replaced and thus not able to load the XML.

<Commercial>
     &lt;Name&gt;Trust &lt;Commercial&gt; Company&lt;/Name&gt;
</Commercial>

I have to read this XML in a XMLDocument object and extract the <Name> element value which is "Trust <Commercial> Company".

This should be read as
<Commercial>
    <Name>Trust <Commercial> Company</Name>
</Commercial>

Would XSLT be required? A .net solution is also welcome.
Please help in suggesting a solution.

Thank you,
rdeveloper

Answer : How to convert a stream with output escaping enabled to proper format XML that can be loaded in a XMLDocument object?

That kinda sucks, especially in this case, where you get "<" and ">" as values as well as node wrappers.

If you replace "<" and ">" universally, then use DOM methods on the resulting XML, you will get an error when you try to get the value from "Commercial.Name". I suppose this could then be an indication that you need to re-format the "Commercial.Name" value by escaping any of the "bad" entities within the node's value, in this case by exchanging "<" and ">" for "<" and ">"...

Seems like a lot of work. I suppose you could "brute force" the replacement, but not before you replace all of the "<" and ">". Then you could pick apart the XML using JavaScript, taking what you want from the appropriate place within the string.

Either way, your work is cut out for you.