Let z=y'', then it simplifies to only a first-order nonlinear ODE:
(x.z' - z)^2 = (z' )^2 + 1
Trial a linear solution for z = Ax+K, and you find it is indeed a solution which results in the condition
K^2 - A^2 = 1.
Then integrate twice to get the y solution:
y(x) = 1/6*A*x^3 + 1/2*sqrt(A^2+1)*x^2 + Bx + C.
Fromage pour moi?